如何从子图流式传输¶
如果您创建了一个包含子图的图,您可能希望从这些子图流式传输输出。为此,您可以在父图的.stream()
方法中指定subgraphs=True
:
环境搭建¶
首先,让我们安装所需的包
为LangGraph开发设置LangSmith
注册LangSmith,可以快速发现和解决您的LangGraph项目中的问题,提高项目性能。LangSmith允许您使用跟踪数据来调试、测试和监控使用LangGraph构建的LLM应用程序——更多关于如何开始的信息,请参阅这里。
示例¶
让我们定义一个简单的例子:
from langgraph.graph import START, StateGraph
from typing import TypedDict
# Define subgraph
class SubgraphState(TypedDict):
foo: str # note that this key is shared with the parent graph state
bar: str
def subgraph_node_1(state: SubgraphState):
return {"bar": "bar"}
def subgraph_node_2(state: SubgraphState):
return {"foo": state["foo"] + state["bar"]}
subgraph_builder = StateGraph(SubgraphState)
subgraph_builder.add_node(subgraph_node_1)
subgraph_builder.add_node(subgraph_node_2)
subgraph_builder.add_edge(START, "subgraph_node_1")
subgraph_builder.add_edge("subgraph_node_1", "subgraph_node_2")
subgraph = subgraph_builder.compile()
# Define parent graph
class ParentState(TypedDict):
foo: str
def node_1(state: ParentState):
return {"foo": "hi! " + state["foo"]}
builder = StateGraph(ParentState)
builder.add_node("node_1", node_1)
builder.add_node("node_2", subgraph)
builder.add_edge(START, "node_1")
builder.add_edge("node_1", "node_2")
graph = builder.compile()
API Reference: START | StateGraph
我们现在从图中流式传输输出:
你可以看到我们只从父图节点 (node_1
和 node_2
) 发出了更新。要从 子图 节点发出更新,你可以指定 subgraphs=True
:
((), {'node_1': {'foo': 'hi! foo'}})
(('node_2:b692b345-cfb3-b709-628c-f0ba9608f72e',), {'subgraph_node_1': {'bar': 'bar'}})
(('node_2:b692b345-cfb3-b709-628c-f0ba9608f72e',), {'subgraph_node_2': {'foo': 'hi! foobar'}})
((), {'node_2': {'foo': 'hi! foobar'}})